+# SPDX-License-Identifier: GPL-3.0-or-later
+#
+# This file is part of Nominatim. (https://nominatim.org)
+#
+# Copyright (C) 2025 by the Nominatim developer community.
+# For a full list of authors see the git log.
+"""
+Simple dict-based implementation of a trie structure.
+"""
+from typing import TypeVar, Generic, Tuple, Optional, List, Dict
+from collections import defaultdict
+
+T = TypeVar('T')
+
+
+class SimpleTrie(Generic[T]):
+ """ A simple read-only trie structure.
+ This structure supports examply one lookup operation,
+ which is longest-prefix lookup.
+ """
+
+ def __init__(self, data: Optional[List[Tuple[str, T]]] = None) -> None:
+ self._tree: Dict[str, 'SimpleTrie[T]'] = defaultdict(SimpleTrie[T])
+ self._value: Optional[T] = None
+ self._prefix = ''
+
+ if data:
+ for key, value in data:
+ self._add(key, 0, value)
+
+ self._make_compact()
+
+ def _add(self, word: str, pos: int, value: T) -> None:
+ """ (Internal) Add a sub-word to the trie.
+ The word is added from index 'pos'. If the sub-word to add
+ is empty, then the trie saves the given value.
+ """
+ if pos < len(word):
+ self._tree[word[pos]]._add(word, pos + 1, value)
+ else:
+ self._value = value
+
+ def _make_compact(self) -> None:
+ """ (Internal) Compress tree where there is exactly one subtree
+ and no value.
+
+ Compression works recursively starting at the leaf.
+ """
+ for t in self._tree.values():
+ t._make_compact()
+
+ if len(self._tree) == 1 and self._value is None:
+ assert not self._prefix
+ for k, v in self._tree.items():
+ self._prefix = k + v._prefix
+ self._tree = v._tree
+ self._value = v._value
+
+ def longest_prefix(self, word: str, start: int = 0) -> Tuple[Optional[T], int]:
+ """ Return the longest prefix match for the given word starting at
+ the position 'start'.
+
+ The function returns a tuple with the value for the longest match and
+ the position of the word after the match. If no match was found at
+ all, the function returns (None, start).
+ """
+ cur = self
+ pos = start
+ result: Tuple[Optional[T], int] = None, start
+
+ while True:
+ if cur._prefix:
+ if not word.startswith(cur._prefix, pos):
+ return result
+ pos += len(cur._prefix)
+
+ if cur._value:
+ result = cur._value, pos
+
+ if pos >= len(word) or word[pos] not in cur._tree:
+ return result
+
+ cur = cur._tree[word[pos]]
+ pos += 1