require 'xml/libxml'
include ConsistencyValidations
-
- set_table_name 'current_relations'
+ include NotRedactable
+
+ self.table_name = "current_relations"
belongs_to :changeset
- has_many :old_relations, :foreign_key => 'id', :order => 'version'
+ has_many :old_relations, :order => 'version'
- has_many :relation_members, :foreign_key => 'id', :order => 'sequence_id'
- has_many :relation_tags, :foreign_key => 'id'
+ has_many :relation_members, :order => 'sequence_id'
+ has_many :relation_tags
has_many :containing_relation_members, :class_name => "RelationMember", :as => :member
has_many :containing_relations, :class_name => "Relation", :through => :containing_relation_members, :source => :relation, :extend => ObjectFinder
# and manually set to false before the actual delete.
relation.visible = true
+ # Start with no tags
+ relation.tags = Hash.new
+
+ # Add in any tags from the XML
pt.find('tag').each do |tag|
raise OSM::APIBadXMLError.new("relation", pt, "tag is missing key") if tag['k'].nil?
raise OSM::APIBadXMLError.new("relation", pt, "tag is missing value") if tag['v'].nil?
# if there are left-over tags then they are new and will have to
# be added.
tags_changed |= (not tags.empty?)
- RelationTag.delete_all(:id => self.id)
+ RelationTag.delete_all(:relation_id => self.id)
self.tags.each do |k,v|
tag = RelationTag.new
+ tag.relation_id = self.id
tag.k = k
tag.v = v
- tag.id = self.id
tag.save!
end
# members may be in a different order and i don't feel like implementing
# a longest common subsequence algorithm to optimise this.
members = self.members
- RelationMember.delete_all(:id => self.id)
+ RelationMember.delete_all(:relation_id => self.id)
members.each_with_index do |m,i|
mem = RelationMember.new
- mem.id = [self.id, i]
+ mem.relation_id = self.id
+ mem.sequence_id = i
mem.member_type = m[0]
mem.member_id = m[1]
mem.member_role = m[2]